8x^2-104x+335=0

Solution for 8x^2-104x+335=0 equation:

8x^2-104x+335=0

a = 8; b = -104; c = +335;
Δ = b2-4ac
Δ = -1042-4·8·335
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-4\sqrt{6}}{2*8}=\frac{104-4\sqrt{6}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+4\sqrt{6}}{2*8}=\frac{104+4\sqrt{6}}{16}
$